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September 18, 2006
Bit of Fun ...
Looking out of my window into a November-grey, misty afternoon in September I thought it would be a good idea to share some fun with you on the blog at least. Here's another one of my beloved brain teasers:
Four children called Evelin, Claudia, Martin and Karsten are playing outside in the garden. Suddenly Karsten asks: "By the way, how old is each one of you three?"
Evelin is the first to answer: "In three years Martin will be exactly the age I was when Claudia was as old as Martin will be in seven years."
And Claudia adds: "A year ago I was exactly twice as old as Martin and Evelin together." (A little hint: as old as Martin and Evelin were together a year ago.)
How old is each of the three?
Only positive integers count as solution. Have fun! It sounds easy and straightforward, I know, but it kept my humans quite busy for some time. Little puffs of smoke coming out of their ears ... Hrrmmmpfff!
Posted by Mausi at September 18, 2006 12:11 PM
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Comments
I love math problems. But at 9:30pm, I am not able to work it out... ugh... I'll give it a shot tomorrow!
Posted by: vw bug at September 20, 2006 01:44 AM
after 45 min. I'd like to point out that this is a trick question, as you generally do not give a child's age as "0"
However, the correct current ages are:
Martin is 1 (hence he didn't pipe up)
Evelin is 5
Claudia is 9
Posted by: caltechgirl at September 20, 2006 05:54 PM
Congratulations, caltechgirl! I see your point about the age of 0 years. But that's because only integers are allowed as solution in this puzzle. We could well imagine that Martin is a year and a day old.
Posted by: Mausi at September 20, 2006 07:42 PM